Experiment 2Bench 2MZU-PE / XRD-2Shutter closed
X-ray Bragg Diffraction
θ–2θ Powder Diffractometer
Run a θ–2θ scan with a Cu Kα tube and locate the Bragg reflections on the chart recorder.
- Duration
- 3 hours
- Kittel
- Chapter 2
- Topics
- Bragg's lawX-ray diffractionPowder method
Key Equations
Constructive interference occurs only when the path difference between rays from adjacent planes is a whole number of wavelengths. Diffraction is therefore impossible unless .
Systematic absences come from the structure factor: BCC keeps only even, FCC only all even or all odd, and diamond additionally kills all-even reflections unless .
Analysis & Reflection
Analysis questions
- Plot against for the reflections you indexed in Task B. What is the slope, and what physical quantity does it represent?
- Visible light has and a typical plane spacing is . Use the condition you found in Task C to show why visible light cannot diffract from a crystal.
- Compare the Fe and Al scans. Fe is missing every reflection with h+k+l odd and Al is missing every mixed-parity reflection. Explain both patterns of absences in terms of a plane of atoms halfway between the ones you are indexing.
- Silicon is missing (200) and (222) even though both satisfy the FCC rule. What does that tell you about the second atom in the diamond basis?
- When you heated the NaCl specimen, the peaks moved to lower 2θ and the high-angle ones lost height. Account for both effects.
Physics problems
- Aluminium is FCC with . Calculate and the Bragg angle for the (111) reflection with Cu Kα, then check both against the instrument.
- Neutrons of wavelength 1.80 Å can be used instead of X-rays. What extra information do neutrons give that X-rays cannot? Think about magnetic as well as nuclear scattering.
- A crystal expands by 0.5% on heating. Use to estimate the shift, in degrees, of a peak that sat at 2θ = 45°.
- Describe in plain language what the Ewald sphere represents, and state the condition under which a reciprocal lattice point lies on it.