PHYS 4801 Simulation Laboratory
Experiment 2Bench 2MZU-PE / XRD-2Shutter closed

X-ray Bragg Diffraction

θ–2θ Powder Diffractometer

Run a θ–2θ scan with a Cu Kα tube and locate the Bragg reflections on the chart recorder.

Duration
3 hours
Kittel
Chapter 2
Topics
Bragg's lawX-ray diffractionPowder method

Goniometer — plan view

Copper Kα, λ = 1.5406 Å · specimen: Sodium chloride powder

0306090120150180BEAM STOP2θ = 28.0°nNACLθ = 14.00°CuX-RAY TUBEDETECTORSHUTTER CLOSED

Chart recorder

θ–2θ scan · 10° to 140° · 0.25° step

ONOFF
hkl

No trace — press START SCAN

19 allowed reflections

Detector electronics

Scintillation counter + ratemeter

Detector angle 2θ
deg
Specimen angle θ
deg
Count rate
c/sPK
d from Bragg
Å
Wavelength λ
Å
sin θ
Indexing

Nearest reflection

(111)

h²+k²+l²

3

d = a/√(h²+k²+l²)

3.2564Å

a at 293 K

5.6402Å

Rock salt. The all-odd reflections are weak because the Na and Cl scattering factors subtract.

Diffractometer control

MZU-PE / XRD-2

Ionising radiation. The shutter will not open until the tube high voltage is on.

ONOFF
Tube HV
OPENSHUT
Shutter

Tube high voltage is off

X-ray tube
Anode
Voltage40 kV
Current30 mA
Specimen stage
Sample rack
Specimen temp293 K
Count time1.00 s
Goniometer drive
Detector angle 2θ28.00 °

Key Equations

2dhklsinθ=nλ2d_{hkl}\sin\theta = n\lambda

Constructive interference occurs only when the path difference between rays from adjacent planes is a whole number of wavelengths. Diffraction is therefore impossible unless λ2d\lambda \le 2d.

dhkl=ah2+k2+l2d_{hkl}=\frac{a}{\sqrt{h^2+k^2+l^2}}

Systematic absences come from the structure factor: BCC keeps only h+k+lh+k+l even, FCC only h,k,lh,k,l all even or all odd, and diamond additionally kills all-even reflections unless h+k+l=4nh+k+l = 4n.

Procedure

0/4

Table 2 — Bragg reflections

0 entries

Sit on a peak with PEAK SEARCH and let the ratemeter settle before you record.

#SpecimenTubeλ/ Åhkl/ °θ/ °sin θd (Bragg)/ ÅRate/ c/sT/ K
No readings yet — set the controls, then press “Record reading”.

Analysis & Reflection

Analysis questions

  1. Plot sinθ\sin\theta against 1/d1/d for the reflections you indexed in Task B. What is the slope, and what physical quantity does it represent?
  2. Visible light has λ5000 A˚\lambda \approx 5000\ \text{Å} and a typical plane spacing is d3 A˚d \approx 3\ \text{Å}. Use the condition you found in Task C to show why visible light cannot diffract from a crystal.
  3. Compare the Fe and Al scans. Fe is missing every reflection with h+k+l odd and Al is missing every mixed-parity reflection. Explain both patterns of absences in terms of a plane of atoms halfway between the ones you are indexing.
  4. Silicon is missing (200) and (222) even though both satisfy the FCC rule. What does that tell you about the second atom in the diamond basis?
  5. When you heated the NaCl specimen, the peaks moved to lower 2θ and the high-angle ones lost height. Account for both effects.

Physics problems

  1. Aluminium is FCC with a=4.05 A˚a = 4.05\ \text{Å}. Calculate d111d_{111} and the Bragg angle for the (111) reflection with Cu Kα, then check both against the instrument.
  2. Neutrons of wavelength 1.80 Å can be used instead of X-rays. What extra information do neutrons give that X-rays cannot? Think about magnetic as well as nuclear scattering.
  3. A crystal expands by 0.5% on heating. Use 2dsinθ=λ2d\sin\theta = \lambda to estimate the shift, in degrees, of a peak that sat at 2θ = 45°.
  4. Describe in plain language what the Ewald sphere represents, and state the condition under which a reciprocal lattice point lies on it.